Specific Heat of an Unknown Metal

The purpose of this lab was to use the specific heat equation to find the specific heat of an unknown metal.
     Background: 
                                      Specific Heats                      J/g°C
                                      Water                                    4.184
                                      Aluminium                              0.894
                                      Brass                                     0.385
                                      Copper                                  0.385
                                      Lead                                      0.129
                                      Stainless Steal                        0.490
                                      Zinc                                       0.390
Specific Heat Equation:
                              Qw= MwCw(/\T)w
Procedure:

•  Choose metal
• Weigh empty beaker
• Weigh beaker with 125 mL water in it
• Weigh metal
• Weigh beaker with metal and water in it
• Find initial water temp
• Heat  beaker with water and metal in it
• When water boils, turn off hot plate and measure water temperature with probe
• Take metal out of heated water, drop into second beaker of room temperature water
• Record temp change in second beaker with temperature probe
• Clean up materials

Data:

• Beaker- 96.273g
• Water- 124mL
• Beaker w/water- 217.01g
• Metal- 87.466g
• Beaker w/metal w/water- 304.20g

Beaker 1 (Initial temperature) - 21.0 degrees Celsius

Beaker 2 (Initial temperature) - 21.1 degrees Celsius

Boiling water w/metal - 99.9 degrees Celsius

Metal in 2nd Beaker - 22.5 degrees Celsius

Calculations:
          (Refer to data above)
                22.5 degrees Celsius - 21.1 degrees Celsius= 1.4 degrees Celsius
                217.01g beaker/H2O - 96.273g beaker = 120.737g Water
                120.737g H2O x 4.184 x 1.4 = 707.23
We predicted that our metal was Lead not only because of the heat retained, but also because it wrote like a pencil. It left a significant amount of black on anything it touched.
                 

Reaction on Barium Chloride and Copper(II) Sulfate

 Obtain two beakers which hold 100mL of liquid each
 Put 35mL Barium Chloride in one beaker, and 35mL of Copper (II) Sulfate in the other (for measurement purposes).
Pour the two together in one beaker, and record any changes you see, hear, or feel on the outside of the beaker.
Clean up materials, making sure to properly dispose of chemicals used.
CuSO4 +BaCl2---> BaSO4 + CuCl
Formation of a precipitate
Should see a cloudy blue liquid form

Once we put the Barium Chloride and Copper(II) Sulfate together, they began to form together. At first, they looked separated, but within a few seconds it almost looked like the chemicals were pushing into each other. The color was a really light blue at first, but got a tiny bit darker within 5-10 minutes.

We left the precipitate in a plastic cup for about two weeks, and it began to oxidize, and get harder and turn a thicker color of blue.



This is our solution right after we mixed the barium chloride and copper (II) sulfate together.